3.205 \(\int \frac {\log (x) \text {Li}_n(a x)}{x} \, dx\)

Optimal. Leaf size=20 \[ \log (x) \text {Li}_{n+1}(a x)-\text {Li}_{n+2}(a x) \]

[Out]

ln(x)*polylog(1+n,a*x)-polylog(2+n,a*x)

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Rubi [A]  time = 0.02, antiderivative size = 20, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 11, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {2383, 6589} \[ \log (x) \text {PolyLog}(n+1,a x)-\text {PolyLog}(n+2,a x) \]

Antiderivative was successfully verified.

[In]

Int[(Log[x]*PolyLog[n, a*x])/x,x]

[Out]

Log[x]*PolyLog[1 + n, a*x] - PolyLog[2 + n, a*x]

Rule 2383

Int[(((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.)*PolyLog[k_, (e_.)*(x_)^(q_.)])/(x_), x_Symbol] :> Simp[(PolyL
og[k + 1, e*x^q]*(a + b*Log[c*x^n])^p)/q, x] - Dist[(b*n*p)/q, Int[(PolyLog[k + 1, e*x^q]*(a + b*Log[c*x^n])^(
p - 1))/x, x], x] /; FreeQ[{a, b, c, e, k, n, q}, x] && GtQ[p, 0]

Rule 6589

Int[PolyLog[n_, (c_.)*((a_.) + (b_.)*(x_))^(p_.)]/((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[PolyLog[n + 1, c*(a
+ b*x)^p]/(e*p), x] /; FreeQ[{a, b, c, d, e, n, p}, x] && EqQ[b*d, a*e]

Rubi steps

\begin {align*} \int \frac {\log (x) \text {Li}_n(a x)}{x} \, dx &=\log (x) \text {Li}_{1+n}(a x)-\int \frac {\text {Li}_{1+n}(a x)}{x} \, dx\\ &=\log (x) \text {Li}_{1+n}(a x)-\text {Li}_{2+n}(a x)\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 20, normalized size = 1.00 \[ \log (x) \text {Li}_{n+1}(a x)-\text {Li}_{n+2}(a x) \]

Antiderivative was successfully verified.

[In]

Integrate[(Log[x]*PolyLog[n, a*x])/x,x]

[Out]

Log[x]*PolyLog[1 + n, a*x] - PolyLog[2 + n, a*x]

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fricas [F]  time = 0.69, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\log \relax (x) {\rm polylog}\left (n, a x\right )}{x}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(x)*polylog(n,a*x)/x,x, algorithm="fricas")

[Out]

integral(log(x)*polylog(n, a*x)/x, x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\log \relax (x) {\rm Li}_{n}(a x)}{x}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(x)*polylog(n,a*x)/x,x, algorithm="giac")

[Out]

integrate(log(x)*polylog(n, a*x)/x, x)

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maple [F]  time = 0.04, size = 0, normalized size = 0.00 \[ \int \frac {\polylog \left (n , a x \right ) \ln \relax (x )}{x}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(ln(x)*polylog(n,a*x)/x,x)

[Out]

int(ln(x)*polylog(n,a*x)/x,x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\log \relax (x) {\rm Li}_{n}(a x)}{x}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(x)*polylog(n,a*x)/x,x, algorithm="maxima")

[Out]

integrate(log(x)*polylog(n, a*x)/x, x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.05 \[ \int \frac {\ln \relax (x)\,\mathrm {polylog}\left (n,a\,x\right )}{x} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((log(x)*polylog(n, a*x))/x,x)

[Out]

int((log(x)*polylog(n, a*x))/x, x)

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sympy [A]  time = 2.33, size = 15, normalized size = 0.75 \[ \log {\relax (x )} \operatorname {Li}_{n + 1}\left (a x\right ) - \operatorname {Li}_{n + 2}\left (a x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(ln(x)*polylog(n,a*x)/x,x)

[Out]

log(x)*polylog(n + 1, a*x) - polylog(n + 2, a*x)

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